Respuesta :
Let x be the speed when Fritz is driving
x + 6 will be the train speed
Converting minutes to hrs
48 mins = 48/60 = 4/5 hrs
40 mins = 40/60 = 2/3 hrs
Remember formula distance = rate * time
distance driving = (4/5)x
distance train traveling = (2/3)(x+6)
The train travels the same distance as the car
4/5x = 2/3(x+6)
4/5x = 2/3x + 4
4/5x - 2/3x = 4
basic elementary school math
2/15x = 4
2x = 40
x = 30 miles/hrs is the speed he driving.
distance train traveling = 2/3(30 + 6) = 24 miles
check with the distance he driving
4/5(30) = 24 miles
x + 6 will be the train speed
Converting minutes to hrs
48 mins = 48/60 = 4/5 hrs
40 mins = 40/60 = 2/3 hrs
Remember formula distance = rate * time
distance driving = (4/5)x
distance train traveling = (2/3)(x+6)
The train travels the same distance as the car
4/5x = 2/3(x+6)
4/5x = 2/3x + 4
4/5x - 2/3x = 4
basic elementary school math
2/15x = 4
2x = 40
x = 30 miles/hrs is the speed he driving.
distance train traveling = 2/3(30 + 6) = 24 miles
check with the distance he driving
4/5(30) = 24 miles
The distance traveled by Fritz to work is 24 miles
Drive time = 48 minutes = (48/60) hours = 0.8 hours
Train time = 40 minutes = (40/60) hours = 0.666 hours
Let :
Car speed = x
Train speed = x + 6
Recall :
Distance = speed × time
Since distance is the same, then ;
Train distance = car distance
(0.6666 × (x + 6)) = 0.8x
0.6666x + 4 = 0.8x
4 = 0.8x - 0.6666x
4 = 0.13333x
x = (4 ÷ 0.13333)
x = 30 mph
The distance traveled = speed × time = 0.8 × 30 = 24 miles
Therefore, distance traveled is 24 miles
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