When fritz drives to work his trip takes 48 ​minutes, but when he takes the train it takes 40 minutes. find the distance fritz travels to work if the train travels an average of 6 miles per hour faster than his driving. assume that the train travels the same distance as the car?

Respuesta :

Let x be the speed when Fritz is driving
x + 6 will be the train speed
Converting minutes to hrs
48 mins = 48/60 = 4/5 hrs
40 mins = 40/60 = 2/3 hrs

Remember formula distance = rate * time
distance driving = (4/5)x
distance train traveling = (2/3)(x+6)

The train travels the same distance as the car
4/5x = 2/3(x+6)
4/5x = 2/3x + 4
4/5x - 2/3x = 4
basic elementary school math
2/15x = 4
2x = 40
x = 30 miles/hrs is the speed he driving.
distance train traveling = 2/3(30 + 6) = 24 miles 
check with the distance he driving
4/5(30) = 24 miles

fichoh

The distance traveled by Fritz to work is 24 miles

Drive time = 48 minutes = (48/60) hours = 0.8 hours

Train time = 40 minutes = (40/60) hours = 0.666 hours

Let :

Car speed = x

Train speed = x + 6

Recall :

Distance = speed × time

Since distance is the same, then ;

Train distance = car distance

(0.6666 × (x + 6)) = 0.8x

0.6666x + 4 = 0.8x

4 = 0.8x - 0.6666x

4 = 0.13333x

x = (4 ÷ 0.13333)

x = 30 mph

The distance traveled = speed × time = 0.8 × 30 = 24 miles

Therefore, distance traveled is 24 miles

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