Question

Find the equation that is equivalent to the quadratic equation shown. Explain why
x² - 6x - 27 = 0
A.) x(x - 3) = 27
B.) (x - 6)² = 63
C.) (x - 3)² = 36
D.) (x - 3)² = 28

Answer 1

C - (x-3)^2=36

If we expand (x-3)^2=36:

(x-3)(x-3)=36
x^2-3x-3x+9=36
x^2-6x+9=36

Then subtract 36

x^2-6x-27=0