There are 8 students in a classroom, including the triplets Molly, Polly, and Dolly. If 3 of the 8 are randomly selected to give speeches, what is the probability that Molly will be first, Polly will be second, and Dolly will be third?
The way you figure this out is that the first person picked has a 1/8 chance, the second would be 1/7 (one person already went) and the third person would have a 1/6 chance (two people already went). To find the probability of this happening would be all the odds multiplied together, so (1/8)*(1/7)*(1/6) which equals 1/336
