Pat helps run an animal shelte.The actual number of animals brought in during a particular month was 150. The percent error was 12%. If pat estimated on the high side (more than 150), how many animals did Pat think were brought to the shelter
Let us assume the number of animals that Pat miscalculated = x The number of actual animals bought during a particular month = 150 Percentage of error that was made by Pat = 12% Number of animals miscalculated by Pat can be written as 100x/12 = 150 100x = 150 * 12 x = 1800/100 = 18 Then The the number of animals that Pat thought were brought to the shelter = 150 + 18 = 168 So Pat miscalculated the number of animals that were brought to the shelter was 168.