Question

the bottom h must be multiplied.$\frac{6h ^{2} }{2h ^{8}h h }$

Answer 1

$\frac{6h ^{2} }{2h ^{8}h h}= = \frac{6h^2}{2h^8h^2} = \frac{6h^2}{2h^{10}} = \frac{3h^2}{h^{10}} = \frac{3}{h^8} = \boxed{\boxed{\bf{3h^{-8}}}}$