Question

*****25 POINTS*****

Write the complex number in the form a + bi.

square root of six(cos 315° + i sin 315°)

A) square root of three over two minus square root of three over two times i
B) square root of six minus square root of sixi
C) square root of three minus square root of threei
D) square root of six over two minus square root of six over two times i

Answer 1

The initial expression is

√6 *(cos 315° + i sin 315°)

We just multiply the factor to express it in the a + ib form

√6 *cos 315° + i √6 *sin 315°

This is equal to √6 *(√2/2) +i √6 *(-√2/2) = √3 -i√3

Answer 2

Answer:

it is C i took the test

Step-by-step explanation: