Question

The school's lemonade is $10\%$ lemon juice by volume, and the rest is sugar water. how many liters of lemon juice must be added to 20 liters of sugar water to make the school's lemonade?

Answer 1

The percentage of lemon in the juice is 10%
The percentage of water sugar is (100-10)=90%
The quantity of lemon in 20 liters of sugar water will be:
amount=(percentage of lemon)/(percentage of sugar water)×(amount of sugar water)
=10/90×20
=2 2/9 liters 

Answer 2

Solution:

As, it is given that school's lemonade is $10\%$ lemon juice by volume, and the rest is sugar water.

School's lemonade which is Sugar water= (100-10)=90 % volume

Let total volume of Lemonade (Lemon Juice + Sugar Water) = x liter

Volume percent of Lemon Juice = $\frac{\text{Percentage of Volume of Lemonade}}{\text{Percent of Volume of Sugar solution}}\times 100$

= $\frac{10}{90}\times 100=\frac{100}{9}$%

Let , number of liters of lemon juice must be added to 20 liters of sugar water to make the school's lemonade= x liter

To find , number of liters  of lemon juice must be added to 20 liters of sugar water to make the school's lemonade, we will use the following formula:

→Volume percent of Lemon Juice = $\frac{\text{ Volume of Lemonade}}{\text{ Volume of Sugar solution}}\times 100$

= $\frac{100}{9}=\frac{x}{20}\times 100\\\\ x=\frac{20}{9}$

= 2.23 Liter(Approx)