Question

Write and solve an inequality for the following: A fish tank can hold at most 315 gallons of water. if a hose is filling the fish tank at a rate of 15 gallons every 10 minutes, how many hours can the hose be left on before the tank overflows?

Answer 1

Step 1

Find the unit rate

$\frac{15}{10} \frac{gallons}{minute}= \frac{1.5}{1} \frac{gallons}{minute}$

Step 2

Convert  $\frac{gallons}{minute}$ to $\frac{gallons}{hour}$

we know that

$1\ hour=60\ minutes$

so

$\frac{1.5}{1} \frac{gallons}{minute}=\frac{1.5}{(1/60)} =60*1.5=90\frac{gallons}{hour}$

Step 3

Find the inequality

Let

x--------> the time in hours

$90x < 315$ ------> this is the inequality

Step 4

Solve the inequality

$90x < 315$

Divide by $90$ both sides

$90x/90 < 315/90$

$x < 3.5\ hours$

therefore

the answer is

Hose can be left on before tank overflows less than $3.5\ hours$

Answer 2

Answer:

5  or 6 hours

Step-by-step explanation:

So the most you can fill up is 315 gallons of water, then 15 gallons every 10 minutes so.... how much times does 10 go into 315 31 and a half times so it would take 32 of those to over fill it. That means we have to convert now, it will be 5 or 6 hours sorry I miss counted try on of those! I hope I could help have a great rest of your day or night!! :))