Question

A car loses value each year the value of the car (t) years ‏ can be modeled using the function f(t)=15000(0.85) ^t. If Elizabeth wants to sell her car in 2 1/3 years what will the cars value be when she sells it?

Answer 1

f(t)=15000(0.85) ^t   =>  f(t) = $15000(0.85) ^t

Substitute 2 1/3 for t in this equation.  This is equivalent to 7/3.

 f(7/3) = $15000(0.85)^(7/3)
           = $10266.02  (answer)