First, we can find the opposite side of the ABC triangle by setting up this ratio:
[tex]tan(30) = \frac{BC}{48} [/tex]
Solve for BC:
[tex]48tan(30) = BC = 27.71[/tex]
Now, we can set up the ratio for the triangle BCD and solve for angle D:
[tex]tan(D) = \frac{27.71}{16} [/tex]
Solve for D:
[tex]D = tan^{-1}( \frac{27.71}{16} ) = 59.99 [/tex]
Since it says round to the nearest degree, the answer's 60°.
