The sum of angles in a triangle add up to 180°, therefore to find the value of x we proceed as follows; sum of angles in ΔABC will be: 48+(6x-28)+2x=180 putting like terms together we get 48-28+6x+2x=180 20+8x=180 8x=180-20 8x=160 x=160/8 x=20° hence: ∠B=(6x-28)=6×20-28=92° ∠C=2x=2×20=40°