Question

What concept does this math problem fall under?

Solve for X:

1/x-c=1/k

Answer 1

it fals under algebra: solving for the unknown so
$\frac{1}{x}-c= \frac{1}{k}$
basically, we should try to isolate 1x on one side so something like
x=something so

$\frac{1}{k}$-c=$\frac{1}{k}$
try to isolate x so
add c to both sides
$\frac{1}{x}$-c+c=$\frac{1}{k}$+c
1/x=$\frac{1}{k}$+c
multiply both sides by x
x/x=($\frac{1}{k}$+c)x
1=($\frac{1}{k}$+c)x
divide both sides by (1/k+c)
$\frac{1}{ \frac{1}{k}+c }$=x
simplify
combine denoenator
$c= \frac{ck}{k} , \frac{1}{k}+c= \frac{1}{k}+ \frac{ck}{k}$
now invert and multiply
$\frac{1}{ \frac{1+ck}{k} }=1 \times \frac{k}{1+ck}= \frac{k}{1+ck}$
x=$\frac{k}{1+ck}$