Question

Nala can spend no more than $150 per month on gasoline. She has already purchased $60 in gas this month. Which inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30?


30n + 60 > 150

30n + 60 < 150

60n + 30 < 150

60n + 30 > 150

Answer 1

Hello!
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I do believe the answer will be 30n + 60 < 150
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Hope this helps! :)

Answer 2

Answer:

tex]60+30n<150[/tex]

Step-by-step explanation:

Given :

Nala can spend no more than $150 per month on gasoline.

She has already purchased $60 in gas this month.

To Find:Which inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30

Solution :

Since we are given that she already purchased for $60 in this month

Let now she will purchase n number of fill ups for the rest days of this month.

since cost of each fill up is $30

So, cost of n fill ups is 30 n

So, total she she spent this month = 60+30n

We are also given that she can spend no more than $150 per month.

So, inequality becomes:

$60+30n<150$

Hence , inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30:

$60+30n<150$

SO, option B is correct .