x^2 - 3x + p = 0
x^2 + qx + 7 = 0
αβ = p..........................(1)
3α + 3β = -q..................(2)
3α3β = 9αβ = 7
so substituting for αβ from (1):-
9p = 7
p = 7/9
α + β = 3 ( from first equation)
from (2) -q = 3 (α + β)
so -q = 3*3 = 9 and q = -9
Answer is p = 7/9 and q = -9
