Question

How many nitrogen atoms are in a 3.37 mol sample of N2O?

Answer 1

Using a Avagadros number

Answer 2

Answer: $40.6\times 10^{23}$ atoms

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles. and weighs equal to the molecular mass.

1 mol of $N_2O$ contains = $2\times 6.023\times 10^{23}=12.046\times 10^{23}$ atoms of nitrogen

3.37 mol of $N_2O$ contains = $\frac{12.046\times 10^{23}}{1}\times 3.37=40.6\times 10^{23}$ atoms of nitrogen

Thus the number of nitrogen atoms in a 3.37 mol sample of $N_2O$ is $40.6\times 10^{23}$