Question

Calculate the mass of water produced when 7.66 g of butane reacts with excess oxygen

Answer 1

2C4H10+13O2---›8CO2 +10H2O
n(C4H10)=m/M=7,66g/58g/mol=0,132mol
n(H2O)=5n(C4H10)=0,66mol
m(H2O)=n*M=0,66mol*18g/mol≈11,87g