y = 2x - 11
4x + 3y = -13
To solve this system using substitution, substitute (2x - 11) into the second equation for y and solve algebraically for x.
4x + 3y = -13 (given)
4x + 3(2x - 11) = -13 (substitute)
4x + 6x - 33 = -13 (distribute)
10x - 33 = -13 (collect like terms)
10x = 20 (add 33 to both sides)
x = 2 (divide both sides by 10)
Substitute 2 for x into either of the original equations.
y = 2x - 11 (given)
y = 2(2) - 11 (substitute)
y = 4 - 11 (multiply)
y = -7 (subtract)
Answer:
x = 2 and y = -7; (2, -7).
