Respuesta :
Answer:
[tex]\sqrt{x^{13}} = x^{6} * \sqrt{x}[/tex].
Step-by-step explanation:
Given : [tex]\sqrt{x^{13} }[/tex].
To find : Simplify this radical.
Solution : We have given [tex]\sqrt{x^{13} }[/tex].
By the exponent same base rule : [tex]x^{a} * x^{b} = x^{a +b}[/tex].
Then we can write 13 as 12 + 1
[tex]x^{12} * x^{1} = x^{12+1}[/tex].
[tex]x^{12} * x^{1} = x^{13}[/tex].
[tex]\sqrt{x^{13}} = \sqrt{x^{12}* x^{1} }[/tex].
By the radical rule : [tex]\sqrt{x^{a}* x^{b} } = \sqrt{x^{a}} * \sqrt{x^{b}}[/tex].
Then ,
[tex]\sqrt{x^{13}} = \sqrt{x^{12}} * \sqrt{x}[/tex].
[tex]\sqrt{x^{13}} = x^{\frac{12}{2}} * \sqrt{x}[/tex].
[tex]\sqrt{x^{13}} = x^{6} * \sqrt{x}[/tex].
Therefore, [tex]\sqrt{x^{13}} = x^{6} * \sqrt{x}[/tex].