Question

100 g of water (specific heat =4.184J/g) and 100g of a metal sample (specific heat = 0.397 J/g) are heated from 25 to 75. Which substance required more thermal energy to reach 75? (Explain your reasoning).

Answer 1

Q=heat and Q=m*c*dekta(temp)
So we have

Q= 100g*4.184*50=20920J of heat energy

Q= 100g * 0.397* 50= 1985J of heat energy

So the water requires more energy and this is due to the higher heat capacity value of water than the metal sample

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Answer 2

Water will require more thermal energy to reach 75 degrees celsius than metal as the energy required by water is 20.9 J and for metal is 2.0 J.

What is thermal energy?

Thermal energy is the energy that is confined to the system because of the temperature. Heat is calculated as,

$\rm Q = mc \Delta T$

For water:

Mass (m) = 0.1 kg

Specific heat (c) = 4.184 J/ gC

Difference in temperature = 50 degrees celsius

$\rm Q = 0.1 \times 4.184 \times 50 = 20.9\;\rm J$

For metal:

Mass (m) = 0.1 kg

Specific heat (c) = 0.397 J/ gC

Difference in temperature = 50 degrees celsius

$\rm Q = 0.1 \times 0.397 \times 50 = 2.0\;\rm J$

Therefore, water has more heat compared to metal.

Learn more about the heat here:

https://brainly.com/question/2273318

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