Question

A flask contains 0.330 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask. express your answer numerically in molecules.

Answer 1

One mole of br2 contains 6.02 * 10^23 Avogadro particles 
It follows that 0.330 moles contains X.  
Hence it follows that X = 0.330 * 6.02 * 10^23 
X = 1.9866 * 10^23 
X = 198660000000000000000000

Answer 2

The number of bromine molecules present in the flask is 1.99 × 10²³ molecules

From the question,

We are to determine the number of bromine molecules present in 0.330 mol of liquid bromine.

From the formula

$Number\ of\ moles = \frac{Number\ of\ molecules}{Avogadro's\ constant}$

We can write that

Number of molecules = Number of moles × Avogadro's constant

From the given information

Number of moles of bromine present = 0.330 mol

and

Avogadro's constant = 6.022 × 10²³ mol⁻¹

∴ Number of molecules of bromine present = 0.330 ×  6.022 × 10²³

Number of molecules of bromine present = 1.98726 × 10²³ molecules

Number of molecules of bromine present ≅ 1.99 × 10²³ molecules

Hence, the number of bromine molecules present in the flask is 1.99 × 10²³ molecules

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