A town population has been increasing at a constant (linear) rate. In 2010 the population was 46,020. By 2012 the population has increased to 52,070. Assume this trend continues. A.) The town’s predicted population in the year 2020 is? B.) In what year will the town’s predicted population be 103495?

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21-01-2018
Mathematics

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A town population has been increasing at a constant (linear) rate. In 2010 the population was 46,020. By 2012 the population has increased to 52,070. Assume this trend continues. A.) The town’s predicted population in the year 2020 is? B.) In what year will the town’s predicted population be 103495?

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glitterbutt02 glitterbutt02 · Answer 1 · 2018-01-21T22:50:38+01:00

glitterbutt02 glitterbutt02

21-01-2018

Ok, so I could be wrong, but you take 52,070 - 46,020 to get the population increase. (6,050) then multiply it times 8 to get to the population of 2020. for B, just do the same thing, but you'll have to subtract 2020 from 103495 to get your number you need to multiply. (6,050 times ____) Again, I could be totally wrong, but that's how I would do it.

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