Question

NEED ASAP, WILL GIVE BRAINLIEST ANSWER


A car of weight 12kN is parked on an uphill road. The road is inclined at an angle of 10° to the horizontal. Use a geometrical method to calculate the perpendicular component of the car's weight acting on the slope and also the force od friction of the road acting on the car's tyres.

Answer 1

12kN is equal to 12000 N
and the perpendicular component will be
mgcos@
mg = 12000 N
cos10°= 0.984
thus it will be 12000*0.984 = 11808N
the frictional force will be
mgsin@
sin10° = 0.1736
and hence it will be = 2083N