A chemist has one solution that is 25% salt and 75% water and another solution that is only 5% salt. How many milliliters of each should the chemist use to make 1400 ml of a solution that is 10% salt.
Let x= number if mL of the first solution. 1400-x= number of mL of second solution. Equation: (1/4)x + (1/20)(1400-x) = 140 (1/4)x + 70 - (1/20)x = 140 (4/20)x =70 (1/5)x = 70 x = 350 350 mL of first 1050 mL of second