Complete the similarity statement for the two triangles shown. Enter your answer in the box.
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Answer:
In the given figure:
In triangle DPL
DP = 45 ft , DL = 25 ft and LP = 45 ft.
In triangle QAZ
QA = 18 ft, QZ = 10 ft and AZ = 22 ft.
Similar triangles states that the two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion.
In triangle DPL and triangle QAZ
Corresponding Angles:
[tex]\angle D = \angle Q[/tex]
[tex]\angle P = \angle A[/tex]
[tex]\angle L = \angle Z[/tex]
Now, to find the corresponding sides:
[tex]\frac{DP}{QA} = \frac{45}{18} = \frac{5}{2}[/tex]
[tex]\frac{PL}{AZ} = \frac{55}{22} = \frac{5}{2}[/tex]
[tex]\frac{DL}{QZ} = \frac{25}{10} = \frac{5}{2}[/tex]
Since, the corresponding sides are in proportion i.e,
[tex]\frac{DP}{QA}=\frac{PL}{AZ}=\frac{DL}{QZ}[/tex]
then, by Similar triangle definition:
[tex]\triangle DPL \sim \triangle QAZ[/tex]