Earth's gravitational field is 7.51 n/kg at the altitude of the space shuttle. what is the size of the force of attraction between a student of mass 54 kg and earth? answer in units of n.

According to this law, each particle attracts each other particles of earth in the universe. The force by which they attract each other is called the force of attraction.

This force is directly proportional to the product of both particles masses and inversely proportional to the square of distance between them. It can be given as,

[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]

Here, (G) is the gravitational constant, (m₁, m₂) are the masses of particles and (r) is the distance between them.

Earth's gravitational field is 7.51 n/kg the altitude of the space shuttle. The mass of the student is 54 kg and the mass of earth is 5.9722×10²⁴ kg.

The maximum operation altitude of the space shuttle is 960 km. Plug in the values in the above formula,

[tex]F=7.51\times\dfrac{5.9722\times10^{24}\times54}{(960\times10^3)^2}\\F=2.63\times10^{15}\rm \; N[/tex]

Thus, the size of the force of attraction between a student which has mass 54 kg and the Earth is 2.63×10¹⁵ N.

Learn more about the Newton's law of gravitation here;

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