Jim and his dad are bricklayers. Jim can lay bricks for a fireplace and chimney in 5 days. With his father's help he can build it in 2 days. How long would it take his father to build it alone?

Respuesta :

we are given

Jim can lay bricks for a fireplace and chimney in 5 days

Jim's 1 day work is

[tex] =\frac{1}{5} [/tex]

we are given

With his father's help he can build it in 2 days

so, both can do same work in 2 days

so, both's 1 day work is

[tex] =\frac{1}{2} [/tex]

Let's assume

his father to build it alone in x days

his father 1 day work is

[tex] =\frac{1}{x} [/tex]

so, both's 1 days work is

[tex] =\frac{1}{x}+\frac{1}{5} [/tex]

so, we can set it to 1/2

we get

[tex] \frac{1}{2}=\frac{1}{x}+\frac{1}{5} [/tex]

now, we can solve for x

[tex] \frac{1}{2}=\frac{5*1}{5*x}+\frac{1*x}{5*x} [/tex]

[tex] \frac{1}{2}=\frac{5+x}{5x} [/tex]

now, we can cross multiply

[tex] 5x=2(5+x) [/tex]

[tex] 5x=10+2x [/tex]

[tex] 3x=10 [/tex]

now, we can solve for x

[tex] x=\frac{10}{3} [/tex]

so,

his father to build it alone is

[tex] =\frac{10}{3}days [/tex]............Answer

ACCESS MORE