Respuesta :
It would be about 8.75 minutes later so round that up to 9 minutes
Solution:
we are given that
My friend sets out walking at a speed of 3 miles per hour.
I set out behind her 5 minutes later at 4 miles per hour.
we have been asked to find
For how many minutes will my friend have been walking when I catch up to her?
Let the required time be t then we can write
As we know that [tex] Distance=Speed*Time [/tex]
When they meet up then difference of distance traveled becomes zero.
so we can write
[tex] 4(t-5)-3t=0\\ \\ 4t-20-3t=0\\ \\ t=20\\ [/tex]
Hence the required time is 20 minutes.