Try this please if you can. Thanks!
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PR ≈ 14.50
Since ∠Q is a right angle, the area can be found from ...
... A = (1/2)bh = (1/2)(QP)(PR)
From trigonometry, we know ...
... QP = PR·cos(P) = PR·cos(36°)
... QR - PR·sin(P) = PR·sin(36°)
Substituting these values and the given area into the area formula gives ...
... 50 = (1/2)(PR·cos(36°))(PR·sin(36°))
... 100/(sin(36°)cos(36°)) = (PR)²
... PR = 10/√(sin(36°)cos(36°))
... PR ≈ 14.5015