Two objects a and b have the same size and shape, but a is twice as heavy as
b. when they are dropped simultaneously from a tower, they reach the ground at the same time. which has a greater momentum?
By definition we have that momentum is the product of the mass of the object by the velocity of the object. In other words: p = m * v Both objects have the same speed because they reach the ground at the same time. However, object a is heavier than object b. The weight of the objects is: a = 2m b = m Therefore the momentum of a and b is pa = 2mv pb = mv Object a has the greatest momentum Answer pa> pb 2mv> mv
In general momentum is defined as the product of mass and velocity. It is expressed as momentum (P) = mass ( m in Kgs) *velocity ( v in m/s)
ie P = m * v kgm/s
Given : Two objects of same size and shape a and b
The velocity of the both the bodies are same ie velocity =v1 = v2=v -eqn 1
But they differ in heaviness as follows : The heaviness of the object a is two times of b
ie a =2b or a/b = 2 or a : b = 2 : 1 mass of the body m1= 2a --eqn-2
momentum of the body is a (P1)= 2m1* v
mass of the body m2= b --eqn 3
momentum of the body b (P2) = m1 * v
the momentum of the two bodies are P1 = P2
ie m1*v1 = m2*v2
P1 : P2 = m1*v1 : m2 * v2
sub the value of v2,v1 from eqn 1, m1=2a, m2=b P1 : P2 = 2av : bv
P1 : P2 = 2a : b ie (P1/P2)= (2a/b) -- eqn 4 Ans :- from the above eqn 4 -it is obvious the momentum of body a is twice of body b ie momentum of the body a is greater.
