Question

Assume that charge −q is placed on the top plate, and +q is placed on the bottom plate. what is the magnitude of the electric field e between the plates? express e in terms of q and other quantities given in the introduction, in addition to ϵ0 and any other constants needed.

Answer 1

B?) Electric field E = q / (εo*A)

C) V = E*d = q*d / (εo*A)

D) V = q / C
so C = q / V = q * 1/V = q*εo*A / q*d = εo*A / d

I hope this helps! ^_^

Answer 2

The magnitude of the electric field between the plates is ; $E = q / ( e_{0}*A )$

Given that :

charge -q is placed on top plate

charge +q is placed on bottom plate

Representing the magnitude of E in respect to q , A and eo

where A = plate area

          q = charge on plate

E = F / q

F = electric force = K (q₁ * q₂) / D²

q = test charge

also V = E * d

          = ( q * d ) / ( e₀ * A )

∴ expressing E in respect to q , A and e₀

$E = q / ( e_{0}*A )$

Hence we can conclude that The magnitude of the electric field between the plates is ; $E = q / ( e_{0}*A )$

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