Question

Calculate the average velocity in m/y of a tectonic plate that has travelled 9000 km to the south in 60 million years

Answer 1

The distance covered by the tectonic plate, in meters, is
$d=9000km=9\cdot 10^6 m$
 The time taken for the tectonic plate to cover this distance is equal to
$t=60 mil.y=60 \cdot 10^6 y$
Therefore, the average velocity of the tectonic plate is the ratio between the distance covered and the time taken: 
$v= \frac{S}{t} = \frac{9\cdot 10^6m}{60 \cdot 10^6y} =0.15 m/y.$

Answer 2

The average velocity of the tectonic plate that has travelled 9000 km to the south in 60 million years is 0.15 m/y

Average velocity can be obtained by dividing the total displacement travelled by the total time taken to cover the displacement. This can be obtained expressed as:

$Ave. Velocity = \frac{Total displacement }{total time}$

• With the above formula, we can obtain the average velocity of the tectonic plate as illustrated below:

Total Displacement = 9000 km due south

= 9000 × 1000 = 9000000 m

Total time = 60 million years

= 60000000 years

Average velocity =?

$Ave. Velocity = \frac{Total displacement}{total time} \\\\ Ave. Velocity = \frac{9000000}{60000000}$

Average velocity = 0.15 m/y

Therefore, the average velocity of the tectonic plate is 0.15 m/y.

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