Question

A hammer taps on the end of a 4.00-m-long metal bar at room temperature. a microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. the pulses are separated in time by 1 1.0 ms. what is the speed of sound in this metal?

Answer 1

Length that is distance s = 4.00m
 Speed of sound in air V = 343 m/s
 Time for metal = 11.0ms = 0.011
 Calculating the time t = s / V = 4 / 343 = 0.01166s
 Time for the sound in the metal = 0.01166 - 0.011 = 0.00066 = 6.6 x 10^-4s Speed of sound in metal Vm = 4 / 6.6 x 10^-4 = 6.060 x 10^3 m/s

Answer 2

We have that the Speed of sound in the metal  is mathematically given as

V=5263.2m/s

Speed

Generally the equation for the  time is mathematically given as

$T=\frac{d}{v}\\\\Therefore\\\\T=\frac{4}{343}\\\\T=11.66\\\\Hence\\\\V=\frac{d}{dt}\\\\V=\frac{4.0}{11.66-10.9}$

V=5263.2m/s

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