The trigonometric properties of a triangle represents the ratios between the different sides of a triangle, hence, the value of,
[tex]sin(L)=\dfrac{4}{5}\\cos(L)=\dfrac{3}{5}\\tan(L)=\dfrac{4}{3}\\[/tex]
Given information:
The triangle LMN is given in the question.
The measurement of side LM is 15 units
The measurement of side LN is 25 units
The measurement of side MN is 20 units
As the trigonometric properties of a triangle states that the value of sin , cos and tan for the respective angle can be written as,
[tex]\bold{sin(L)=\dfrac{\text{Perpendicular}}{\text{Hypotenuse}}}\\\\\bold{cos(L)=\dfrac{\text{Base}}{\text{Hypotenuse}}}\\\\\\\bold{tan(L)=\dfrac{\text{Perpendicular}}{\text{Base}}}\\[/tex]
Using the above trigonometric properties, the value of,
[tex]sin(L)=\dfrac{25}{20}\\sin(L)=\dfrac{4}{5}\\[/tex]
Similarly, the value of cos(L),
[tex]cos(L)=\dfrac{15}{25}\\cos(L)=\dfrac{3}{5}[/tex]
And,the value of tan(L) is,
[tex]\\tan(L)=\dfrac{20}{15}\\tan(L)=\dfrac{4}{3}[/tex]
Hence, the required values in the triangle LMN are,
[tex]\bold{sin(L)=\dfrac{4}{5}}\\\bold{cos(L)=\dfrac{3}{5}}\\\bold{tan(L)=\dfrac{4}{3}}\\[/tex]
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