Question

a 0.12 kg bird is flying at a constant speed of 7.8 m/s. what is the birds conetic energy?

Answer 1

KE=1/2mv^2 - equation for kinetic energy
KE=(1/2)(0.12 kg)((7.8 m/s)^2 - plug it into the formula
KE=(0.06 kg)(60.84 m/s) - multiply 1/2 to the mass and square the speed
KE= 3.7 J - answer
Hope this helps

Answer 2

Answer:

3.6504 Joules is the birds kinetic energy.

Explanation:

Mass of the bird, m  = 0.12 kg

Speed by which bird is flying , v = 7.8 m/s

The kinetic energy of the flying bird is given by :K.E

$K.E.=\frac{1}{2}mv^2$

$K.E.=\frac{1}{2}\times 0.12 kg\times (7.8 m/s)^=3.6504 Joules$

3.6504 Joules is the birds kinetic energy.