We have to find the volume of oblique cone. An oblique cone is a special type of cone in which the apex is not located directly above the center of the circular base, so it looks like a slanted cone.
Volume of oblique cone = [tex] \frac{1}{3} \Pi r^{2}h [/tex]
where 'r' is the radius and 'h' is the height.
Here r = 6 cm and h = 10 cm
Volume = [tex] \frac{1}{3} (\Pi (6)^{2} \times 10) [/tex]
= [tex] \frac{360\Pi }{3} [/tex]
= [tex] 120\Pi cm^{3} [/tex]
So, the volume of the given oblique cone is [tex] 120\Pi cm^{3} [/tex].
Option 4 is the correct answer.
The volume of the oblique cone whose radius is 6 cm and the height of the cone is 10 cm is 376.9911 cm³.
An oblique cone is a special type of cone whose vertex is not aligned in the center. The volume of an oblique cone is given as,
[tex]\text{Volume of oblique cone} = \dfrac{1}{3}\pi r^2 h[/tex]
We know that the radius of the given oblique cone is 6 cm while the height of the cone is 10 cm, therefore, substitute the values in the formula of the volume of the oblique cone, we get
[tex]\text{Volume of oblique cone} = \dfrac{1}{3}\pi r^2 h[/tex]
[tex]\text{Volume of oblique cone} = \dfrac{1}{3}\pi \times(6)^2 \times 10[/tex]
[tex]=120 \pi\rm\ cm^3\\\\= 376.9911\ cm^3[/tex]
Hence, the volume of the oblique cone whose radius is 6 cm and the height of the cone is 10 cm is 376.9911 cm³.
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