Question

the expression x^3-64 can be written as (x)^3-(4)^3. what is the factorization of x^3-64?
a^3-b^3=(a-b)(a^2-ab+b^2)
A) (x-4)(x^2+4x+8)
B) (x-4)(x^2+4x+16)
C) (x-4)(x^2+64x+16)
D) (x-4)(x^2+64x+4096)

Answer 1

It's B Bro.....................