Here we shall use basic Proportionality theorem.
The ratio of the intercepts formed by two transversals for three parallel lines are in the same proportion.
As BC || CD
By Basic Proportionality theorem we get
[tex] \frac{AB}{BD} =\frac{AC}{CE} [/tex]
Here AB = 15, BD = 6, AC = 25
Substituting the values we get
[tex] \frac{15}{6}\frac{25}{CE} [/tex]
Cross multiplying we get
15 CE = 25 × 6
15 CE = 150
Dividing by 15 on both sides
CE = 10 Units
Hence the length of CE = 10 units.
