Respuesta :
Let's assume
number of cookies in the beginning =x
Larry ate 1/3 Of the cookies
so, the remaining cookies are
[tex] =x-\frac{1}{3} x [/tex]
[tex] =\frac{2}{3} x [/tex]
now, we have
Barry ate 1/4 Of the remaining cookies
so, the remaining cookies are
[tex] =\frac{2}{3} x-\frac{1}{4}*\frac{2}{3} x [/tex]
[tex] =\frac{2}{3} x-\frac{1}{6} x [/tex]
[tex] =\frac{2*2}{3*2} x-\frac{1}{6} x [/tex]
[tex] =\frac{4}{6} x-\frac{1}{6} x [/tex]
[tex] =\frac{3}{6} x [/tex]
[tex] =\frac{1}{2} x [/tex]
Terry ate 1/2 Of the remaining cookies
so, the remaining cookies are
[tex] =\frac{1}{2} x-\frac{1}{2}*\frac{1}{2} x [/tex]
[tex] =\frac{1}{2} x-\frac{1}{4} x [/tex]
[tex] =\frac{1}{4} x [/tex]
Mrs James found the tray with 6 cookies left
so, the remained cookies =6
so, we get
[tex] \frac{1}{4} x=6 [/tex]
[tex] x=24 [/tex]
Hence ,
number of cookies were on the tray when Mrs James first left it on the counter are 24.............Answer