Mrs james left a tray on the counter early one morning. Larry ate 1/3 Of the cookies. Barry ate 1/4 Of the remaining cookies. them terry ate 1/2 Of the remaining cookies. Mrs james found the tray with 6 cookies left. how many cookies were on the tray when Mrs james first left it on the counter?

Respuesta :

24 cookies were in the beginning.

Let's assume

number of cookies in the beginning =x

Larry ate 1/3 Of the cookies

so, the remaining cookies are

[tex] =x-\frac{1}{3} x [/tex]

[tex] =\frac{2}{3} x [/tex]

now, we have

Barry ate 1/4 Of the remaining cookies

so, the remaining cookies are

[tex] =\frac{2}{3} x-\frac{1}{4}*\frac{2}{3} x [/tex]

[tex] =\frac{2}{3} x-\frac{1}{6} x [/tex]

[tex] =\frac{2*2}{3*2} x-\frac{1}{6} x [/tex]

[tex] =\frac{4}{6} x-\frac{1}{6} x [/tex]

[tex] =\frac{3}{6} x [/tex]

[tex] =\frac{1}{2} x [/tex]

Terry ate 1/2 Of the remaining cookies

so, the remaining cookies are

[tex] =\frac{1}{2} x-\frac{1}{2}*\frac{1}{2} x [/tex]

[tex] =\frac{1}{2} x-\frac{1}{4} x [/tex]

[tex] =\frac{1}{4} x [/tex]

Mrs James found the tray with 6 cookies left

so, the remained cookies =6

so, we get

[tex] \frac{1}{4} x=6 [/tex]

[tex] x=24 [/tex]

Hence ,

number of cookies were on the tray when Mrs James first left it on the counter are 24.............Answer

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