Respuesta :
Let x be the previous high score, that is initially 100%. John beat his previous high score in the favorite game by 28% and the new high score 288 points is 128%. Then you can write it as proportion:
[tex] \dfrac{x}{288} =\dfrac{100}{128} [/tex].
Solve it by cross multiplication:
[tex] 128x=288\cdot 100,\\ 128x=28800,\\ \ \\ x=\dfrac{28800}{128} ,\\ \ \\
x=225 [/tex].
Answer: the previous high score was 225 points.
Let's assume his previous score was x
we are given
John beat his previous high score in the favourite game by 28%
It means that
New score is 28 % greater than previous score
so,
New score = 28 % of previous score + previous score
now , we have assumed
previous score =x
so, we get
New score =[tex] \frac{28}{100}x+x [/tex]
New score =[tex] 0.28x+x [/tex]
New score =[tex] 1.28x [/tex]
now, we are given
New high score is 288 points
so, we can plug it
[tex] 288=1.28x [/tex]
now, we can solve for x
[tex] 288=1.28x [/tex]
Divide both sides by 1.28
[tex] \frac{288}{1.28} =\frac{1.28x}{1.28} [/tex]
we get
[tex] x=225 [/tex]
so,
his previous score was 225 points..........Answer