Answer:
option: A is correct.
Step-by-step explanation:
for the two triangles ΔABC and ΔDBA to be similar the segment AD must be an altitude of ΔABC.
Theorem: If an altitude is drawn from the right angle of any right triangle, then the two triangles formed are similar to the original triangle and all three triangles are similar to each other.
As in ΔABC; ∠A=90° and we draw an altitude from A to the side BC. hence the two triangles formed i.e. ΔDBA and ΔDAC will be similar to ΔABC.
Hence by the theorem it holds that ΔABC is similar to ΔDBA.
Hence, option A is correct.