Respuesta :
hey there!:
The stoichiometry of the reaction is:
TiO2 + 4 Cl2 + 3C = CO2 + 2 CO +2 TiCl4
4 moles Cl2 ----------------- 2 moles TiCl4
115 moles Cl2 --------------- moles TiCl4 ??
moles TiCl4 = 115 * 2 / 4
moles TiCl4 = 230 / 4
=> 57.5 moles of TiCl4
Answer D
hope this helps!
The stoichiometry of the reaction is:
TiO2 + 4 Cl2 + 3C = CO2 + 2 CO +2 TiCl4
4 moles Cl2 ----------------- 2 moles TiCl4
115 moles Cl2 --------------- moles TiCl4 ??
moles TiCl4 = 115 * 2 / 4
moles TiCl4 = 230 / 4
=> 57.5 moles of TiCl4
Answer D
hope this helps!
Answer:
The correct answer is option D. 57.5 mol
Explanation:
Hello!
Let's solve this!
The reaction is as follows:
TiO2 + 4Cl2 + 3C → CO2 + 2CO + 2TiCl4
The data is:
mol Cl2 = 115 mol
In the reaction we see that the ratio of moles is 4 moles of Cl2 resulting in 2 moles TiCl4.
This is represented as follows:
4molCl2 ---- 2molTiCl4
115molCl2 ---- xmolTiCl4
So:
molTiCl4 = 115molCl2 * (2molTiCl4 / 4molCl2) = 57.5molTiCl4
We conclude that the correct answer is option D. 57.5 mol