Question

Determine the molecular formula of a compound with an empirical formula of CH in a formula mass of 78.110 AMU

Answer 1

 Determine the molecular formula of the compound with an empirical formula of CH and a molar mass of 78.110 g/mol. 3. A sample with a molar mass of 34.00 g/mol is found to consist of 0.44g H and 6.92g O. Find its molecular formula.

Answer 2

The molecular formula would be  $C_6H_6$

(empirical formula)n = molecular formula

Where, n = molecular formula mass/empirical formula mass

Empirical formula mass of CH = 1 + 12

                                             = 13 amu

n = 78.110/13

          = 6

Thus, molecular formula = (CH)6

                                            = $C_6H_6$

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