Answer:
(3,2)
Step-by-step explanation:
Let's solve this via elimination method:
[tex]\begin{cases} x+y=5\\x-y=1\end{cases}[/tex]
By subtracting equation 2 from equation one we obtain:
[tex]\begin{cases} x+y=5\\-(x-y=1)\end{cases}\\\\0x+2y=4\\\\y=2[/tex]
Next we can use any equation either 1 or 2 to determine what x is, I'll use equation 1. Let y=2 and so:
[tex]x+y=5\\\\x+2=5\\x=5-2\\\\x=3[/tex]
Therefore the solution for the system of equations is:
x=3 and y = 2 as an ordered pair we have (3,2)