Respuesta :

Answer:

(3,2)

Step-by-step explanation:

Let's solve this via elimination method:

[tex]\begin{cases} x+y=5\\x-y=1\end{cases}[/tex]

By subtracting equation 2 from equation one we obtain:

[tex]\begin{cases} x+y=5\\-(x-y=1)\end{cases}\\\\0x+2y=4\\\\y=2[/tex]

Next we can use any equation either 1 or 2 to determine what x is, I'll use equation 1.  Let y=2 and so:

[tex]x+y=5\\\\x+2=5\\x=5-2\\\\x=3[/tex]

Therefore the solution for the system of equations is:

x=3 and y = 2 as an ordered pair we have (3,2)

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