Question

Elias serves a volleyball at a velocity of 16 m/s. The mass of the volleyball is 0.27 kg. What is the height of the volleyball above the gym floor when its total mechanical energy is 41.70 J? Round to the nearest tenth\

Answer 1

Ingenuity says that the answer is 2.7 m

Answer 2

Answer:

The height of the volleyball above the gym floor is 2.70 m.

Explanation:

Given data:

Velocity of volleyball is, $v=16\;\rm m/s$.

Mass of volleyball is, $m=0.27 \;\rm kg$.

Total mechanical energy is, $T = 41.70 \;\rm J$.

Use conservation of energy as,

Total mechanical energy = kinetic energy + potential energy

$T= KE+PE\\T= \dfrac{1}{2}mv^{2}+mgh$

Here, g is the gravitational acceleration and h is height.

Solving as,

$41.70= \dfrac{1}{2} \times 0.27 \times 16^{2}+(0.27) \times (9.8)h\\h = 2.70 \;\rm m$

Thus, the height of the volleyball above the gym floor is 2.70 m.

For more details, refer the link:

https://brainly.com/question/498695?referrer=searchResults