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I believe the answer is 75%.
Pictures will be in cluded in the attachment below.
The child will be affected by Galactosemia if he/she has at least one dominant gene (G). So:
G g
G GG Gg
g Gg gg
3/4 = 0.75 = 75%
Pictures will be in cluded in the attachment below.
The child will be affected by Galactosemia if he/she has at least one dominant gene (G). So:
G g
G GG Gg
g Gg gg
3/4 = 0.75 = 75%
![Ver imagen andriansp](https://us-static.z-dn.net/files/d48/a8e4b117d1f048910c3616a7ceede8e3.png)
They will have a daughter that is affected with galactosemia with probability of 25%
Further explanation
Heredity is the passing on of traits from parents to their offspring; either through asexual reproduction or sexual reproduction.
A. Sickle cell anemia and albinism are both recessive traits in humans. Imagine that a couple, already pregnant with twins, has just learned that they are both heterozygous for both of these traits. As the couple's genetic counselor, the couple asks you the following questions about how their carrier status will affect their offspring.
The probability that one of the fraternal twins is a carrier of either, but not both, of the conditions? We need to use both the product law and the sum law to answer this question. So for child 2/4 will be that they will be carier and this is true for both so [tex]\frac{2}{4} *\frac{2}{4} = \frac{4}{16}[/tex] will be the answer
If patricia and les have another child, what is the probability that they will have a daughter that is affected with galactosemia?
[tex]\frac{2}{4} *\frac{2}{4} = \frac{4}{16}[/tex]
Learn more
- Learn more about galactosemia https://brainly.com/question/11489167
- Learn more about probability twins https://brainly.com/question/7383606
- Learn more about probability daughter https://brainly.com/question/1303749
Answer details
Grade: 9
Subject: social studies
Chapter: Heredity
Keywords: galactosemia, probability, sickle cell anemia, albinism, humans