We are told the given equation:
[tex]y(t) = 0.2 + 8t - 10t^2[/tex]
When a particle is not moving, the velocity is zero. Thus we have to find the first derivative.
[tex]y'(t) = v(t) = 8-20t[/tex]
Now set v(t) = 0, and we get
[tex]8-20t = 0
[/tex]
8 = 20t
t = 8/20 s
Hope this helps