Question

find the zeros : x(x^2+13x+40)

Answer 1

the zeros are x= 0,-5,-8. the zeros are the x values where the graph intersects the x-axis. to find the zeros, you have to replace y with zero then solve for x.

Answer 2

Given Expression

$\rm \hookrightarrow \: x ( \: x^2+13x+40)$

Can Be Written As

$\rm \hookrightarrow \: {x}^{2} + 13x + 40$

Now,

$\rm \hookrightarrow \: {x}^{2} + 5x + 8x+ 40$

$\rm \hookrightarrow \: {x}(x +5) + 8(8x + 5)$

$\star\boxed{ \rm { \pmb {\pmb {\pmb\pink\hookrightarrow \pink{ \:( x + 5)(x + 8)}}}}}$