given:
x = x1 + (x2 â’ x1)t,
y = y1 + (y2 ⒠y1)t where 0 ≤ t ≤ 1
vertices of triangle a(1, 1), b(5, 3), c(1, 7).
solution:
for getting AB apply points a and b in the above equations,
then x=1+4t , y=1+2t
for getting BC apply points b and c in the equations
then x=5-4t, y=3+4t
for getting CA apply points c and a in the equations
then x=1, y=7-6t
Answer:
equations for AB is x=1+4t , y=1+2t
equations for BC is x=5-4t, y=3+4t
equations for CA is x=1, y=7-6t