Answer:
We heated up the liquid CFC from 11.05 degrees celsius to its boiling point (47.6 degrees)
That means we heated it up 36.55 degrees
The formula to solve this is C = Q / M x dT
where
C is the specific heat of the liquid CFC (.91 J/G/C)
Q is the amount of heat required (what we're trying to find out)
M is the mass (52.5 grams)
and dT is the temperature difference (36.55 degrees)
Now put in the values and find out what Q is
.91 = Q / 52.5 x 36.55
.91 = Q / 1918.875
Q = 1746.17 joules to heat up the liquid CFC
