Question

The density of silver is 10.5 g/cm3. what would be the mass (in grams) of a piece of silver that occupies a volume of 23.6 cm3?

Answer 1

hey there : !

density = 10.5 g/cm³

volume = 23.6 cm³

therefore:

D = m / V

10.5 = m / 23.6

m = 10.5 * 23.6

m = 247.8 g

hope this helps!

Answer 2

Answer:

Mass, m = 247.8 grams

Explanation:

It is given that,

Density of silver, $d=10.5\ g/cm^3$

Volume occupies by the silver, $V=23.6\ cm^3$

We need to find the mass of a piece of silver. The formula for the density is given by :

$d=\dfrac{m}{V}$

$m=d\times V$

$m=10.5\times 23.6$

m = 247.8 g

So, the mass of the piece of the silver is 247.8 grams. Hence, this is the required solution.